Ace Your C++ Skills 2026 – Rock the ‘Thinking in C++’ Challenge!

If the static integer is initialized at 0, each time the function is called it will increment the value by 1. Therefore, the first call will print 1, the second call will print 2, and so on until the tenth call which will print 10. This is because the static integer will retain its value between function calls. Option A is incorrect because it will print numbers 1 to 10, not 0 to 9. Option B is incorrect because it will only print the number 10, not numbers 1 to 10. Option D is incorrect because it will only print the number 1, not numbers 1 to 10.